Give the number of electrons in the species $H_{2}^{+}$,$H_{2}$,and $O_{2}^{+}$.
(N/A) $H_{2}^{+}$:
Number of electrons in $H$ atom is $1$. Total electrons in $H_{2} = 1 + 1 = 2$. Since it is a cation $(H_{2}^{+})$,remove $1$ electron. Total electrons = $2 - 1 = 1$.
$H_{2}$:
Number of electrons in $H$ atom is $1$. Total electrons in $H_{2} = 1 + 1 = 2$.
$O_{2}^{+}$:
Number of electrons in $O$ atom is $8$. Total electrons in $O_{2} = 8 + 8 = 16$. Since it is a cation $(O_{2}^{+})$,remove $1$ electron. Total electrons = $16 - 1 = 15$.
Number of electrons in $H$ atom is $1$. Total electrons in $H_{2} = 1 + 1 = 2$. Since it is a cation $(H_{2}^{+})$,remove $1$ electron. Total electrons = $2 - 1 = 1$.
$H_{2}$:
Number of electrons in $H$ atom is $1$. Total electrons in $H_{2} = 1 + 1 = 2$.
$O_{2}^{+}$:
Number of electrons in $O$ atom is $8$. Total electrons in $O_{2} = 8 + 8 = 16$. Since it is a cation $(O_{2}^{+})$,remove $1$ electron. Total electrons = $16 - 1 = 15$.
Explore More
Similar Questions
Olfactoreceptors are:
Given that:
$2C_{(s)} + 2O_{2(g)} \to 2CO_{2(g)}; \Delta H = -787 \ kJ$
$H_{2(g)} + 1/2 O_{2(g)} \to H_2O_{(l)}; \Delta H = -286 \ kJ$
$C_2H_{2(g)} + 2.5 O_{2(g)} \to 2CO_{2(g)} + H_2O_{(l)}; \Delta H = -1301 \ kJ$
Calculate the heat of formation of acetylene $(C_2H_{2(g)})$ in $kJ$.
$2C_{(s)} + 2O_{2(g)} \to 2CO_{2(g)}; \Delta H = -787 \ kJ$
$H_{2(g)} + 1/2 O_{2(g)} \to H_2O_{(l)}; \Delta H = -286 \ kJ$
$C_2H_{2(g)} + 2.5 O_{2(g)} \to 2CO_{2(g)} + H_2O_{(l)}; \Delta H = -1301 \ kJ$
Calculate the heat of formation of acetylene $(C_2H_{2(g)})$ in $kJ$.
When the temperature of a black body increases,it is observed that the wavelength corresponding to maximum energy changes from $0.26 \mu m$ to $0.13 \mu m$. The ratio of the emissive powers of the body at the respective temperatures is
In an $ac$ circuit $I = 100 \sin(200 \pi t)$. The time required for the current to achieve its peak value will be
The tyre of a motor car contains air at $15^{\circ} C$. If the temperature increases to $35^{\circ} C$,the approximate percentage increase in pressure is (ignore the expansion of the tyre).
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo